- #1

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Is g'Bg >= g'g ?

Thanks,

Karthik

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- Thread starter Karthiksrao
- Start date

- #1

- 68

- 0

Is g'Bg >= g'g ?

Thanks,

Karthik

- #2

Hurkyl

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No wait, 0x0 matrices are too simple. Let's try the next simplest case -- 1x1 matrices.

Try analyzing the 1x1 case. What do you see?

- #3

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- #4

Hurkyl

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Anyways, rather than looking at 1x1 matrices one at a time, you should try proving it for all 1x1 matrices at once! You'll need to introduce one or more additional variables, of course.

- #5

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Yeah.. Understood. Eigen values of B has to be greater than 1 for the relation to hold true.

Thanks

Thanks

- #6

Hurkyl

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I believe that statement.

- #7

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if the eigenvalues of B is larger than 1, the statement holds. Otherwise, it does not.

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